如何判断一个app是否是今天首次启动

另外一个做费，用这个

<script>  
var today = new Date(),  
Now=today.getFullYear()+"."+today.getMonth()+"."+today.getDate();  
(localStorage.t)?  
(function(){  
        (localStorage.t == Now)?  
        console.log(true):  
        (function(){  
                localStorage.num = 0;  
                localStorage.t = Now;  
        })();  
        localStorage.num = Number(localStorage.num) + 1;  
})():  
(function(){  
        localStorage.t = Now;  
        localStorage.num = 1;  
})();  
alert("今天是你第" + localStorage.num + "次打开App了！");  
</script>

<script>  
var today = new Date(),  
Now=today.getFullYear()+"."+today.getMonth()+"."+today.getDate();  
(localStorage.t)?  
(_=>{  
        (localStorage.t == Now)?  
        console.log(true):  
        (_=>{  
                localStorage.num = 0;  
                localStorage.t = Now;  
        })();  
        localStorage.num = Number(localStorage.num) + 1;  
})():  
(_=>{  
        localStorage.t = Now;  
        localStorage.num = 1;  
})();  
alert("今天是你第" + localStorage.num + "次打开App了！");  
</script>

本地做一个启动时间变量，每次启动都检查这个时间并写入启动时间，就可以知道是否今天第一次启动。另外要考虑用户从23点一直使用APP到明天1点的情况，还要考虑用户让APP一直在后台挂着跨天的情况

localstorage 不行吗？