问题描述:
这个页面我有四个选项卡,每个选项卡内容相同,只是排序不同,我想这个四个选项卡都实现上拉刷新功能,应该怎么修改代码呢?
还有就是我现在 “综合” 这个选项卡第一个li就是ltem11,请问这是怎么回事呢?
下面是源代码:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8" />
<meta name="viewport" content="width=device-width,initial-scale=1.0,maximum-scale=1.0,user-scalable=no" />
<title>b2b2c商城卖家版_分销列表</title>
<link rel="stylesheet" href="../css/mui.min.css">
<link rel="stylesheet" href="../css/common.css" />
<link rel="stylesheet" href="../css/list.css" />
<script type="text/javascript" src="../js/common.js"></script>
</head>
<body>
<header class="mui-bar mui-bar-nav">
<a class="mui-action-back mui-icon mui-icon-back mui-pull-left"></a>
<h1 class="mui-title">分销商品列表</h1>
</header>
<div class="mui-content">
<div style="padding: 10px 10px; margin-top: 40px;">
<div id="segmentedControl" class="mui-segmented-control mui-segmented-control-inverted">
<a class="mui-control-item mui-active" href="#item1">
综合
</a>
<a class="mui-control-item" href="#item2">
销量
</a>
<a class="mui-control-item" href="#item3">
佣金
</a>
<a class="mui-control-item" href="#item4">
价格
</a>
</div>
</div>
<div>
<div id="item1" class="mui-control-content mui-active">
<div class="mui-scroll">
<ul class="mui-table-view">
</ul>
</div>
</div>
<div id="item2" class="mui-control-content">
<ul class="mui-table-view">
<li class="mui-table-view-cell">
第二个选项卡子项-1
</li>
<li class="mui-table-view-cell">
第二个选项卡子项-2
</li>
<li class="mui-table-view-cell">
第二个选项卡子项-3
</li>
<li class="mui-table-view-cell">
第二个选项卡子项-4
</li>
<li class="mui-table-view-cell">
第二个选项卡子项-5
</li>
</ul>
</div>
<div id="item3" class="mui-control-content">
<ul class="mui-table-view">
<li class="mui-table-view-cell">
第三个选项卡子项-1
</li>
<li class="mui-table-view-cell">
第三个选项卡子项-2
</li>
<li class="mui-table-view-cell">
第三个选项卡子项-3
</li>
</ul>
</div>
<div id="item4" class="mui-control-content">
<ul class="mui-table-view">
<li class="mui-table-view-cell">
第四个选项卡子项-1
</li>
<li class="mui-table-view-cell">
第四个选项卡子项-2
</li>
</ul>
</div>
</div>
</div>
<script src="../js/mui.min.js"></script>
<script src="../js/app.js"></script>
<script>
mui.init({
swipeBack: false,
pullRefresh: {
container: '#item1',
up: {
contentrefresh: '正在加载...',
callback: pullupRefresh
}
}
});
var count = 0;
/**
* 上拉加载具体业务实现
*/
function pullupRefresh() {
setTimeout(function() {
mui('#item1').pullRefresh().endPullupToRefresh((++count > 2)); //参数为true代表没有更多数据了。
var table = document.body.querySelector('.mui-table-view');
var cells = document.body.querySelectorAll('.mui-table-view-cell');
for (var i = cells.length, len = i + 10; i < len; i++) {
var li = document.createElement('li');
li.className = 'mui-table-view-cell';
li.innerHTML = '<a class="mui-navigate-right">Item ' + (i + 1) + '</a>';
table.appendChild(li);
}
}, 1000);
}
if (mui.os.plus) {
mui.plusReady(function() {
setTimeout(function() {
mui('#item1').pullRefresh().pullupLoading();
}, 1000);
});
} else {
mui.ready(function() {
mui('#item1').pullRefresh().pullupLoading();
});
}
</script>
</body>
jie (作者)
1.用我现在这种方式不能实现吗?因为我这个页面已经是2级页面了,1级页面也是一个WebView,会不会导致卡顿现象什么的?
2.“document.body.querySelectorAll”这个应该是改成这个 “document.body.querySelector”吗?
2015-03-05 15:51
DCloud_UNI_FXY
1.可以实现。但是这样做的话,下拉刷新只能是在选项卡标题的上边,而不能在选项卡标题的下边
2.document.getElementById('item1').querySelectorAll
2015-03-05 15:54