其实安卓也可以侧滑返回webview窗口

给要侧滑返回的窗口加这个代码

<!doctype html>  
<html>  

    <head>  
        <meta charset="UTF-8">  
        <title></title>  
        <meta name="viewport" content="width=device-width,initial-scale=1,minimum-scale=1,maximum-scale=1,user-scalable=no" />  
        <link href="css/mui.min.css" rel="stylesheet" />  
        <script src="js/mui.min.js"></script>  
        <script type="text/javascript">  
            mui.init();  

            function plusReady() {  
                //获取当前窗口  
                var ws = plus.webview.currentWebview();  
                //监听当前侧滑窗口的右滑  
                ws.drag({  
                    direction: 'right',  
                    moveMode: 'followFinger'  
                }, {  
                    view: plus.runtime.appid,  
                    moveMode: 'silent'  
                }, function(e) {  
                //滑动到end执行mui.back()事件  
                    if(e.type == 'end' && e.result) {  
                        mui.back();  
                    }  
                });  
            }  
            if(window.plus) {  
                plusReady();  
            } else {  
                document.addEventListener("plusready", plusReady, false);  
            }  
        </script>  
    </head>  

    <body>  
        <header class="mui-bar mui-bar-nav">  
            <a class="mui-action-back mui-icon mui-icon-left-nav mui-pull-left"></a>  
            <h1 class="mui-title">窗口侧滑关闭</h1>  
        </header>  
    </body>  

</html>

1***@qq.com

不行呀，我按你这个写个了H5页面不能实现滑动返回上一页呀
提示 [Intervention] Unable to preventDefault inside passive event listener due to target being treated as passive. See
由于目标被视为被动事件侦听器，无法在被动事件侦听器中防止缺省。

附链接测试地址：http://www.wangyl.xyz/al/%E5%8F%B3%E6%BB%91.html

2019-07-01 11:00