如何在IOS的插件代码中打开一个UIViewController的原生界面？

用swift没搞定，用obc就可以，希望对小菜有帮助，大神无视哈

- (void)startBarcode:(PGMethod*)commands  
{  
    if ( commands ) {  

        // CallBackid 异步方法的回调id，H5+ 会根据回调ID通知JS层运行结果成功或者失败  
        NSString* cbId = [commands.arguments objectAtIndex:0];  

        // 用户的参数会在第二个参数传回，可以按照Array方式传入，  
        //NSDictionary* pArray = [commands.arguments objectAtIndex:1];  

        // 如果使用Array方式传递参数  
        //NSString* pResultString = [pArray description];//[NSString stringWithFormat:@"%@ %@ %@ %@",[pArray objectAtIndex:0], [pArray objectAtIndex:1], [pArray objectAtIndex:2], [pArray objectAtIndex:3]];  

        // 运行Native代码结果和预期相同，调用回调通知JS层运行成功并返回结果  
        //PDRPluginResult *result = [PDRPluginResult resultWithStatus:PDRCommandStatusOK messageAsString:pResultString];  

        // 如果Native代码运行结果和预期不同，需要通过回调通知JS层出现错误，并返回错误提示  
        //PDRPluginResult *result = [PDRPluginResult resultWithStatus:PDRCommandStatusError messageAsString:@"惨了! 出错了！ 咋(wu)整(liao)"];  

        //NSLog(@"-------->%@",pArray);  

        //NSData* pa=[self resultWithJSON: pArray];  

        //[obja print:callback: self toCallback: cid:cbId param:pResultString]  

        UIStoryboard* myStoryBoard = [UIStoryboard storyboardWithName:@"Main_iPhone" bundle: nil];  
        QRViewController *controller = [myStoryBoard instantiateViewControllerWithIdentifier:@"qrview"];  
        [controller setcallback:@"qrcode" callback:^( NSString *data) {  
            // request complete  
            NSLog(@"callback is out %@",data);  
            PDRPluginResult *result;  
            result = [PDRPluginResult resultWithStatus:PDRCommandStatusOK messageAsString:data];  

            [self toCallback:cbId withReslut:[result toJSONString]];  

        }];  
        [self presentViewController:controller animated:YES completion:NULL];  

        // 通知JS层Native层运行结果  
        //[self toCallback:cbId withReslut:[result toJSONString]];  

    }  
}  

急！急！急！ 找人离线打包个安卓APP 与 苹果APP HBuilder写的www项目 重谢给米给米啦！有的速度联系我Q 310167130