对于数组对象中，遍历出相同（对象属性）的元素

// 对于数组对象中，查询出name属性值相同的元素  
            let obj = [  
                {  
                    name:"幼儿园",  
                    num:100,  
                    level:1  
                },  
                {  
                    name:"幼儿园1",  
                    num:10,  
                    level:3  
                },  
                {  
                    name:"幼儿园3",  
                    num:110,  
                    level:3  
                },  
                {  
                    name:"幼儿园1",  
                    num:101,  
                    level:2  
                },  
                {  
                    name:"幼儿园",  
                    num:100,  
                    level:1  
                },  
                {  
                    name:"幼儿园4",  
                    num:10,  
                    level:3  
                },  
                {  
                    name:"幼儿园",  
                    num:110,  
                    level:3  
                },  
                {  
                    name:"幼儿园5",  
                    num:101,  
                    level:2  
                },  
                {  
                    name:"幼儿园3",  
                    num:110,  
                    level:3  
                },  
                {  
                    name:"幼儿园5",  
                    num:101,  
                    level:2  
                }  
            ]  
            //利用对象的唯一性  
            // 1.用for+变量  
            let obj2 ={};  
            for (let i = 0; i < obj.length; i++) {  
                if(!obj2[obj[i].name]){  
                    obj2[obj[i].name] = [];  
                    obj2[obj[i].name].push(obj[i]);  
                }else{  
                    obj2[obj[i].name].push(obj[i]);  
                }  
            }  
            console.log(obj2);  

            // 2.reduce()  
            let objs = obj.reduce((total, currentValue,)=>{  

                if(!total[currentValue.name]){  
                    total[currentValue.name] = []  
                    total[currentValue.name].push(currentValue)  
                }else{  
                    total[currentValue.name].push(currentValue)  
                }  
                return total;  
            },{})  
            console.log(objs);  
            // 在去重的基础上再进行获取重复元素  
            let newArr=[],uniArr=[];  
            for (let i = 0; i < obj.length; i++) {  
                let name = obj[i].name;  
                if(!uniArr.includes(name)){  
                    uniArr.push(name);  
                    newArr[uniArr.length-1] = [];  
                    newArr[uniArr.length-1].push(obj[i]);  
                }else{  
                    let index =uniArr.indexOf(name)>-1?uniArr.indexOf(name):0;  
                    newArr[index].push(obj[i]);  
                }  
            }  
            console.log(newArr,uniArr);